Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider the following program of ‘C&rs...
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Consider the following program of ‘C’
main ( )
{
static int a [ ] = { 1, 2, 3, 4, 5, 6, 7, 8 } ;
int i;
for(i = 2; I < 6; ++i)
a [a [i] ] = a [i];
for (I = 0; I < 8 ; ++i)
printf (“%d”, a[i]);
}
The output of the program is :
main ( )
{
static int a [ ] = { 1, 2, 3, 4, 5, 6, 7, 8 } ;
int i;
for(i = 2; I < 6; ++i)
a [a [i] ] = a [i];
for (I = 0; I < 8 ; ++i)
printf (“%d”, a[i]);
}
The output of the program is :
- a)1 2 3 4 5 6 7 8
- b)1 2 3 3 5 5 7 8
- c)1 2 2 3 3 4 4 8
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider the following program of ‘C’main ( ){static int a...
Array a
for(I = 2; I < 6; ++i) // initially i = 2 and 2< 6(true)
a [a [i] ] = a [i];
Iteration 1:
i = 2;
a[a[2]] = a[2]
a[3] = [3]
for(I = 2; I < 6; ++i) // initially i = 2 and 2< 6(true)
a [a [i] ] = a [i];
Iteration 1:
i = 2;
a[a[2]] = a[2]
a[3] = [3]
Iteration 2:
When i = 3, 3 < 6 (true)
a[a[3]] = a[3]
a[3] = 3 // as in iteration 1, a[3] becomes was 3
When i = 3, 3 < 6 (true)
a[a[3]] = a[3]
a[3] = 3 // as in iteration 1, a[3] becomes was 3
Iteration 3:
When i = 4
a[a[4]] = a[4]
a[5] = 5
When i = 4
a[a[4]] = a[4]
a[5] = 5
Iteration 4:
When i = 5, 5 < 6 (true)
a[a[5]] = a[5]
a[5] = 5 // as in iteration 3 a[5] becomes 5.
In next iteration i becomes and condition 6 < 6 false here.
Content of array A are as follows:
Finally, it prints: 1 2 3 3 5 5 7 8
When i = 5, 5 < 6 (true)
a[a[5]] = a[5]
a[5] = 5 // as in iteration 3 a[5] becomes 5.
In next iteration i becomes and condition 6 < 6 false here.
Content of array A are as follows:
Finally, it prints: 1 2 3 3 5 5 7 8
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Community Answer
Consider the following program of ‘C’main ( ){static int a...
Program Analysis
The given C program initializes a static array and modifies it using a loop. Let's break down the steps to understand how the output is generated.
Initialization
- The static array `a` is initialized as follows:
a = {1, 2, 3, 4, 5, 6, 7, 8}
Loop Execution
- The program contains a loop that starts with `i = 2` and runs while `i < 6`.="" the="" loop="" modifies="" the="" array="" as="" />
c
for(i = 2; i < 6;="" ++i)="" />
a[a[i]] = a[i];
}
- Iteration Details:
- i = 2:
- `a[2]` is `3`
- Update `a[3]`: `a[3] = a[2]` → `a[3] = 3` → Array: `{1, 2, 3, 3, 5, 6, 7, 8}`
- i = 3:
- `a[3]` is `3`
- Update `a[3]`: `a[3] = a[3]` (no change) → Array: `{1, 2, 3, 3, 5, 6, 7, 8}`
- i = 4:
- `a[4]` is `5`
- Update `a[5]`: `a[5] = a[4]` → `a[5] = 5` → Array: `{1, 2, 3, 3, 5, 5, 7, 8}`
- i = 5:
- `a[5]` is `5`
- Update `a[5]`: `a[5] = a[5]` (no change) → Array: `{1, 2, 3, 3, 5, 5, 7, 8}`
Final Output
- After the loop, the program prints the contents of the array:
c
for (i = 0; i < 8;="" ++i)="" />
printf("%d", a[i]);
}
- This results in the final output: `1 2 3 3 5 5 7 8`
Conclusion
- The correct answer is option 'B': `1 2 3 3 5 5 7 8`.
The given C program initializes a static array and modifies it using a loop. Let's break down the steps to understand how the output is generated.
Initialization
- The static array `a` is initialized as follows:
a = {1, 2, 3, 4, 5, 6, 7, 8}
Loop Execution
- The program contains a loop that starts with `i = 2` and runs while `i < 6`.="" the="" loop="" modifies="" the="" array="" as="" />
c
for(i = 2; i < 6;="" ++i)="" />
a[a[i]] = a[i];
}
- Iteration Details:
- i = 2:
- `a[2]` is `3`
- Update `a[3]`: `a[3] = a[2]` → `a[3] = 3` → Array: `{1, 2, 3, 3, 5, 6, 7, 8}`
- i = 3:
- `a[3]` is `3`
- Update `a[3]`: `a[3] = a[3]` (no change) → Array: `{1, 2, 3, 3, 5, 6, 7, 8}`
- i = 4:
- `a[4]` is `5`
- Update `a[5]`: `a[5] = a[4]` → `a[5] = 5` → Array: `{1, 2, 3, 3, 5, 5, 7, 8}`
- i = 5:
- `a[5]` is `5`
- Update `a[5]`: `a[5] = a[5]` (no change) → Array: `{1, 2, 3, 3, 5, 5, 7, 8}`
Final Output
- After the loop, the program prints the contents of the array:
c
for (i = 0; i < 8;="" ++i)="" />
printf("%d", a[i]);
}
- This results in the final output: `1 2 3 3 5 5 7 8`
Conclusion
- The correct answer is option 'B': `1 2 3 3 5 5 7 8`.
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